Java中如何获取url问号后的参数和参数名称呢？

实现思路:
    1.使用url的getQuery方法
	2.使用字符串的split方法截取字符串

例:
 http://127.0.0.1:9000/user/userInfoget?userId=888&source=811


//将参数放入map中
public static Map<String, String> splitQuery(URL url) throws UnsupportedEncodingException {
        Map<String, String> query_Pairs = new LinkedHashMap<String, String>();
        String query = url.getQuery();
        String[] pairs = query.split("&");
        for (String pair : pairs) {
            int idx = pair.indexOf("=");
            query_pairs.put(URLDecoder.decode(pair.substring(0, idx), "UTF-8"), URLDecoder.decode(pair.substring(idx + 1), "UTF-8"));
        }
        return query_pairs;
 }

//
 Map<String, String> stringMap = splitQuery(url);
    System.out.println(stringMap.get("userId"));
    System.out.println(stringMap.get("source"));