Java中如何生成Http中Get请求的URL呢?

生成URL的实现思路

方式0:
   字符串拼接组合
方式1:
   使用String.format格式化一个URL
方式2:
   使用URI对象中的构造器方法构造一个URL的链接及参数信息

 
private static String d = "2023-04-14"; 
private static String f = "shenzhen";  
private static String s = "wuhan";  
private static String baseUrl = "https://www.java265.com";
private static String publicName = "/test";
private static String url ="/query"; 

private static String urlSource = baseUrl + publicName  + "%s?" +
		"d=%s&" +
		"f=%s&" +
		"s=%s";


public static void main(String[] args) throws IOException, URISyntaxException {

	String url1 = String.format(urlSource, url, d, f, s);
	System.out.println(getTicketlistUrl);

	//uri的构造器
	URI uri = new URIBuilder()
			.setScheme("https")
			.setHost("www.java265.com")
			.setPath(publicName+url)
			.setParameter("d", d )
			.setParameter("f", f)
			.setParameter("s", s)
			.build();
	System.out.println(uri.toString());
}