java代码如何实现按照指定属性对ArrayList 进行排序呢?

list按照实现属性比对大小的实现思路:
    定义一个比较器类，需实现Comparator方法
	  如:
public class CustomComparator implements Comparator<MyObject> {
    @Override
    public int compare(MyObject o1, MyObject o2) {
        return o1.getStartDate().compareTo(o2.getStartDate());
    }
}


//list比较示例
Collections.sort(Database.ArrayList, new CustomComparator());

list比较2：直接传入一个匿名类

Collections.sort(Database.arrayList, new Comparator<MyObject>() {
    @Override
    public int compare(MyObject o1, MyObject o2) {
        return o1.getStartDate().compareTo(o2.getStartDate());
    }
});

Java8 之 Lambda表达式实现的匿名类

Collections.sort(Database.arrayList, 
      (o1, o2) -> o1.getStartDate().compareTo(o2.getStartDate()));
		或
Database.arrayList.sort((o1, o2) -> o1.getStartDate().compareTo(o2.getStartDate()));