JAVA如何判断一个IP是否为内网IP呢?

1.将IP地址的规则设置到规则表中
2.遍历判断 当前IP是否在规则表中
          如果在规则表中，则可界定为此IP地址是一个内网IP

 
/**
     * 私有IP：
     * A类  10.0.0.0-10.255.255.255  
     * B类  172.16.0.0-172.31.255.255  
     * C类  192.168.0.0-192.168.255.255           
     *
     * 127这个网段是环回地址
     * localhost  
     */
    static list<Pattern> ipFilterRegexList = new ArrayList<>();

    static {
        Set<String> ipFilter = new HashSet<String>();
        ipFilter.add("^10\\.(1\\d{2}|2[0-4]\\d|25[0-5]|[1-9]\\d|[0-9])"
                + "\\.(1\\d{2}|2[0-4]\\d|25[0-5]|[1-9]\\d|[0-9])" + "\\.(1\\d{2}|2[0-4]\\d|25[0-5]|[1-9]\\d|[0-9])$");
        // B类地址范围: 172.16.0.0---172.31.255.255
        ipFilter.add("^172\\.(1[6789]|2[0-9]|3[01])\\" + ".(1\\d{2}|2[0-4]\\d|25[0-5]|[1-9]\\d|[0-9])\\"
                + ".(1\\d{2}|2[0-4]\\d|25[0-5]|[1-9]\\d|[0-9])$");
        // C类地址范围: 192.168.0.0---192.168.255.255
        ipFilter.add("^192\\.168\\.(1\\d{2}|2[0-4]\\d|25[0-5]|[1-9]\\d|[0-9])\\"
                + ".(1\\d{2}|2[0-4]\\d|25[0-5]|[1-9]\\d|[0-9])$");
        ipFilter.add("127.0.0.1");
        ipFilter.add("0.0.0.0");
        ipFilter.add("localhost");
        for (String tmp : ipFilter) {
            ipFilterRegexList.add(Pattern.compile(tmp));
        }
    }



/**
     * 判断IP是否内网IP
     * @Title: ipIsInner
     * @param ip
     * @return: boolean
     */
    public static boolean ipIsInner(String ip) {
        boolean isInnerIp = false;
        for (Pattern tmp : ipFilterRegexList) {
            Matcher matcher = tmp.matcher(ip);
            if (matcher.find()) {
                isInnerIp = true;
                break;
            }
        }
        return isInnerIp;
    }