Java8 lambda表达式详解
下文笔者讲述Java8中Lambda的简介说明,如下所示:
实现Runnable线程
可以使用下面语法实现Lambda:(params) -> expression (params) -> statement (params) -> { statements }例
方法接受两个方法参数 (int t1, int t2) -> t1 + t2 可简写 (int a, int b) -> a + b例: 多线程示例
Java8之前 new Thread(new Runnable() { @Override public void run() { System.out.println("Java8之前代码写法!"); } }).start(); Java8: new Thread(() -> System.out.println("java8")).start();
遍历list集合
Java8 之前 List<String> numbers = Arrays.asList("j", "a", "v", "a"); for (String number : numbers) { System.out.println(number); } Java8: List<String> numbers = Arrays.asList("j", "a", "v", "a"); numbers.forEach(n -> System.out.println(n)); 或使用方法引用操作符号“::” List<String> numbers = Arrays.asList("j", "a", "v", "a"); numbers.forEach(System.out::println);
使用过滤方法
filter过滤数组中大于3的数字 List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5); numbers.stream() .filter((n) -> n > 3) .forEach(System.out::println);
复杂的条件
java.util.function.Predicate提供and(), or() 和 xor()可以进行逻辑操作。 List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5); Predicate<Integer> greater2 = (n) -> n > 2; Predicate<Integer> less4 = (n) -> n < 4; numbers.stream() .filter(greater2.and(less4)) .forEach(System.out::println);
实现 Map 和 Reduce
.map 改变集合元素 List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5); numbers.stream() .map((n) -> n * n) .forEach(System.out::println); .reduce 将计算集合中所有值。 List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5); Integer count = numbers.stream() .map((n) -> n * n) .reduce((sum, n) -> sum + n) .get(); System.out.println(count);集合转换
.collect 变为另一个集合。 List<Integer> oldNumbers = Arrays.asList(1, 2, 3, 4, 5); List<Integer> list = oldNumbers.stream() .map((n) -> n * n) .collect(Collectors.toList()); list.forEach(System.out::println);
整合集合中所有元素为一个字符串
将字符串转换为大写 使用逗号串起来 List<String> strList = Arrays.asList("j", "a", "v","a"); String str = strList.stream() .map(String::toUpperCase) .collect(Collectors.joining(", ")); System.out.println(str);
去除重复的元素
distinct()去除重复元素 List<String> stringList = Arrays.asList("a", "b", "c", "a", "b"); String str = stringList.stream() .map(String::toUpperCase) .distinct() .collect(Collectors.joining(", ")); System.out.println(str);
计算List中元素的最大值,最小值,和,平均值
List<Integer> numbers = Arrays.asList(2, 3, 5, 7, 11, 12, 14, 16, 17, 18); IntSummaryStatistics stats = numbers.stream() .mapToInt((x) -> x) .summaryStatistics(); System.out.println("集合中最大值 : " + stats.getMax()); System.out.println("集合中最小值 : " + stats.getMin()); System.out.println("集合中元素之和 : " + stats.getSum()); System.out.println("集合中元素平均值 : " + stats.getAverage());
排序
创建三个 User 对象,进行姓名排序。 List<User> userList = Arrays.asList( new User("A", 12, Sex.MAN, 2011, 60.5, Arrays.asList("swim","running")), new User("C", 23, Sex.MAN, 2012, 54.3, Arrays.asList("music","riding")), new User("B", 30, Sex.WOMAN, 2010, 48.2, Arrays.asList("swim","programme")) ); userList.stream() .sorted(Comparator.comparing(User::getName)) .forEach(System.out::println);
取最小值
取最小值,不为空则打印 List<User> userList = Arrays.asList( new User("A", 12, Sex.MAN, 2011, 60.5, Arrays.asList("swim","running")), new User("C", 23, Sex.MAN, 2012, 54.3, Arrays.asList("music","riding")), new User("B", 30, Sex.WOMAN, 2010, 48.2, Arrays.asList("swim","programme")) ); userList.stream() .min(Comparator.comparing(User::getAge)) .ifPresent(System.out::println);
取其中一个字段并排序
取其中一个字段并排序 List<User> userList = Arrays.asList( new User("A", 12, Sex.MAN, 2011, 60.5, Arrays.asList("swim","running")), new User("C", 23, Sex.MAN, 2012, 54.3, Arrays.asList("music","riding")), new User("B", 30, Sex.WOMAN, 2010, 48.2, Arrays.asList("swim","programme")) ); userList.stream() .map(User::getName) .sorted() .forEach(System.out::println);
是否符合条件
allMatch是否全部符合条件,是则返回true,但凡有一个不满足则返回false. List<User> userList = Arrays.asList( new User("A", 12, Sex.MAN, 2011, 60.5, Arrays.asList("swim","running")), new User("C", 23, Sex.MAN, 2012, 54.3, Arrays.asList("music","riding")), new User("B", 30, Sex.WOMAN, 2010, 48.2, Arrays.asList("swim","programme")) ); boolean tmp = userList.stream() .allMatch(u -> u.getAge() < 35); System.out.println(tmp);
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