Spring MVC如何编写一个统一的异常处理模块呢？

实现思路:
    使用编写一个实现HandlerExceptionResolver接口的类
	即可达到Spring MVC统一异常处理的效果

只需编写一个实现HandlerExceptionResolver接口的类
  并将此类交给Spring管理，即可实现统一异常处理的效果
 
package com.java265.exception;
 
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.springframework.web.servlet.HandlerExceptionResolver;
import org.springframework.web.servlet.ModelAndView;
/**
 * 利用HandlerExceptionResolver统一处理异常
 * 
 * 要点概述：
 * 1、MyException实现HandlerExceptionResolver接口
 * 2、在MyException类上使用@Component注解
 * 3、在方法resolveException( )处理各类异常
 */
@Component
public class MyException implements HandlerExceptionResolver {
	
	@Override
	public ModelAndView resolveException(HttpServletRequest request, HttpServletResponse response, Object handler,Exception exception) {
		 ModelAndView modelAndView = new ModelAndView();
		 if(exception instanceof ArithmeticException) {
			 modelAndView.addObject("msg", "ArithmeticException");
		 }else if(exception instanceof ArrayIndexOutOfBoundsException){
			 modelAndView.addObject("msg", "ArrayIndexOutOfBoundsException");
		 }
		 modelAndView.setViewName("result");
		 
		return modelAndView;
	} 
}