HttpClient如何采用JSON参数发送POST请求呢?

HttpClient发送POST请求

1.定义请求头为 application/json
2.将json信息放入到请求体中
3.使用HttpClient发送post请求

public static JSONObject httpPost(String url, Map<String, String> params) {
	// post请求返回结果
	CloseableHttpClient httpClient = HttpClientConfig.getHttpClient();
	JSONObject jsonResult = null;
	HttpPost httpPost = new HttpPost(url);
	httpPost.setHeader("Content-type", "application/json; charset=utf-8");
	try {
		if (null != params) {
			// 构建消息实体 Map转json字符串
			StringEntity entity = new StringEntity(JSON.toJSONString(params), charset);
			entity.setContentEncoding("UTF-8");
			// 发送Json格式的数据请求
			entity.setContentType("application/json");
			httpPost.setEntity(entity);
		}
		CloseableHttpResponse response = httpClient.execute(httpPost);
		return convertResponse(response);
	} catch (IOException e) {
		LOGGER.error("post请求提交失败:" + url, e);
	} finally {
		httpPost.releaseConnection();
	}
	return jsonResult;
}

private static JSONObject convertResponse(CloseableHttpResponse response) throws IOException, ParseException {
	// 请求发送成功，并得到响应
	JSONObject jsonObject = new JSONObject();
	if (response.getStatusLine().getStatusCode() == HttpStatus.SC_OK) {
		// 读取服务器返回过来的json字符串数据
		HttpEntity entity = response.getEntity();
		String strResult = EntityUtils.toString(entity, charset);
		// 把json字符串转换成json对象
		jsonObject = JSON.parseObject(strResult);
	}
	jsonObject.put("status",response.getStatusLine().getStatusCode());
	return jsonObject;
}